Double and Triple Integrals

25 min
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A double integral over a region sums a function across a two-dimensional area:

Rf(x,y)dA.\iint_R f(x, y)\, dA.

Over a rectangle you compute it as an iterated integral — integrate the inner variable first (treating the other as constant), then the outer.

Worked example. 0102(x+y)dydx.\displaystyle\int_0^1 \int_0^2 (x + y)\, dy\, dx.

Inner (in yy, with xx fixed): 02(x+y)dy=[xy+y22]02=2x+2.\displaystyle\int_0^2 (x + y)\, dy = \left[ xy + \tfrac{y^2}{2} \right]_0^2 = 2x + 2.

Outer (in xx): 01(2x+2)dx=[x2+2x]01=3.\displaystyle\int_0^1 (2x + 2)\, dx = \left[ x^2 + 2x \right]_0^1 = 3.

A triple integral VfdV\iiint_V f\, dV extends the same idea to a solid — for example, the mass of a body whose density varies from point to point.

Fubini's theorem says that for a continuous function over a rectangle, swapping the order of integration…

Evaluate 0101xydydx.\displaystyle\int_0^1 \int_0^1 xy \, dy \, dx.

Evaluate 0102(x+y)dydx.\displaystyle\int_0^1 \int_0^2 (x + y) \, dy \, dx.

A unit cube occupies 0x,y,z10 \le x, y, z \le 1 with density ρ(x,y,z)=z\rho(x, y, z) = z. Find its mass VzdV.\displaystyle\iiint_V z \, dV.