Pythagoras in 3D Objects

25 min
0/4 practice checks

Pythagoras in 3D Objects

A cuboid's space diagonal can be found by applying Pythagoras to a face diagonal and then to a second right triangle. Only combine lengths that lie in the same right triangle at each step. A careful solution names the quantities, keeps place value or units visible, and explains why each operation fits.

Worked reasoning

  1. The 3×43\times4 face diagonal is 5.
  2. Then 52+122=13\sqrt{5^2+12^2}=13.

Find the space diagonal of a 3×4×123\times4\times12 cuboid.

Which statement best captures the central mathematical idea in Pythagoras in 3D Objects?

When starting a problem about Pythagoras in 3D Objects, which move is most reliable?

Which statement is a misconception that must be rejected when working with Pythagoras in 3D Objects?