Factorising by Grouping

25 min
0/4 practice checks

When an expression has four terms and no single factor common to all of them, group the terms in pairs, factorise each pair, and look for a shared bracket.

Worked example. Factorise ax+ay+bx+byax + ay + bx + by.

  • Group: (ax+ay)+(bx+by)(ax + ay) + (bx + by).
  • Factor each pair: a(x+y)+b(x+y)a(x + y) + b(x + y).
  • Both pairs now share the bracket (x+y)(x + y), so pull it out: (a+b)(x+y)(a + b)(x + y).

The magic is that after factorising each pair, an identical bracket appears in both. That common bracket becomes one factor, and the leftovers become the other.

Factorise x(a+b)+2(a+b)x(a + b) + 2(a + b).

Factorise ax+ay+bx+byax + ay + bx + by. Answer in factored form, e.g. (a+b)(x+y).

Factorise x2+5x+3x+15x^2 + 5x + 3x + 15. Answer in factored form, e.g. (x+3)(x+5).

Factorise 6ab+9a+4b+66ab + 9a + 4b + 6.