Limits and Continuity

25 min
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A limit describes where a function is heading as its input approaches some value — regardless of what happens exactly at that value.

We write

limxaf(x)=L\lim_{x \to a} f(x) = L

to mean: as xx gets arbitrarily close to aa (from either side), f(x)f(x) gets arbitrarily close to LL. Crucially, xx never has to reach aa — the limit is about the approach, not the destination.

Many limits are found by direct substitution when the function behaves nicely: limx4(3x5)=3(4)5=7\lim_{x\to 4}(3x-5) = 3(4)-5 = 7. The interesting cases are where substitution gives 00\tfrac{0}{0} and we must simplify first.

Worked example. Evaluate limx2x24x2\lim_{x\to 2}\dfrac{x^2-4}{x-2}.

Substituting x=2x=2 gives 00\tfrac{0}{0} — undefined, but not hopeless. Factor the numerator:

x24x2=(x2)(x+2)x2=x+2(x2)\frac{x^2-4}{x-2} = \frac{(x-2)(x+2)}{x-2} = x+2 \quad (x \neq 2)

Now substitute: limx2(x+2)=4\lim_{x\to 2}(x+2) = 4. The original function has a hole at x=2x=2, yet it still heads towards 4.

Evaluate limx4(3x5)\lim_{x\to 4}(3x-5).

Evaluate limx2x24x2\lim_{x\to 2}\dfrac{x^2-4}{x-2}.

A function ff is continuous at x=ax=a precisely when:

Evaluate limx3x2+2xx2+1\lim_{x\to\infty}\dfrac{3x^2+2x}{x^2+1}.