Product, Quotient and Chain Rules

25 min
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Three rules let you differentiate combinations of functions.

Product rule: ddx[uv]=uv+uv\dfrac{d}{dx}[u\,v] = u'v + uv'.

Quotient rule: ddx ⁣[uv]=uvuvv2\dfrac{d}{dx}\!\left[\dfrac{u}{v}\right] = \dfrac{u'v - uv'}{v^2}.

Chain rule (a function inside a function): ddxf(g(x))=f(g(x))g(x)\dfrac{d}{dx}f\big(g(x)\big) = f'\big(g(x)\big)\cdot g'(x).

Worked example (chain rule). Differentiate y=(2x+1)3y=(2x+1)^3.

The outer function is 'cube it'; the inner function is 2x+12x+1. Differentiate the outer, keep the inner, then multiply by the inner's derivative:

dydx=3(2x+1)22=6(2x+1)2\frac{dy}{dx} = 3(2x+1)^2 \cdot 2 = 6(2x+1)^2

Worked example (product rule). Differentiate y=(x2+1)(x3)y=(x^2+1)(x-3) with u=x2+1u=x^2+1, v=x3v=x-3:

y=(2x)(x3)+(x2+1)(1)=2x26x+x2+1=3x26x+1y' = (2x)(x-3) + (x^2+1)(1) = 2x^2-6x+x^2+1 = 3x^2-6x+1

Which rule is the efficient tool to differentiate y=(3x+2)5y=(3x+2)^5?

Differentiate y=(2x+1)3y=(2x+1)^3. Give dydx\dfrac{dy}{dx} in factored form.

Differentiate y=(x2+1)(x3)y=(x^2+1)(x-3). Give dydx\dfrac{dy}{dx} as an expanded polynomial.

For y=(x2+1)4y=(x^2+1)^4, find dydx\dfrac{dy}{dx} at x=1x=1.