Area of Triangles

25 min
0/4 practice checks

Area of Triangles

Two congruent triangles form a parallelogram or rectangle, so a triangle has half the area of base times perpendicular height. A=12bhA=\tfrac12 bh, where height is perpendicular to the chosen base. A careful solution names the quantities, keeps place value or units visible, and explains why each operation fits.

Worked reasoning

  1. Use A=12bhA=\tfrac12 bh.
  2. 12(10)(7)=35\tfrac12(10)(7)=35 square centimetres.

Find the area of a triangle with base 10 cm and perpendicular height 7 cm.

Which statement best captures the central mathematical idea in Area of Triangles?

When starting a problem about Area of Triangles, which move is most reliable?

Which statement is a misconception that must be rejected when working with Area of Triangles?