Rationalising Denominators

35 min
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Rationalising Denominators

Rationalising removes a surd from the denominator without changing a value. Multiply numerator and denominator by the same non-zero expression. For a single root use that root; for a binomial denominator use the conjugate, which changes the sign between terms. The product of conjugates gives a difference of squares.

Worked reasoning

35=3555=355\frac{3}{\sqrt5}=\frac{3}{\sqrt5}\cdot\frac{\sqrt5}{\sqrt5}=\frac{3\sqrt5}{5}. The factor 5/5\sqrt5/\sqrt5 is 1, so the fraction stays equivalent.

Exam method

  1. Identify the full denominator. 2. Choose a factor that removes its radical part. 3. Multiply top and bottom, simplify, and leave no radical in the denominator.

Why the denominator matters

The convention of rationalising is not a trick for changing values; it leaves an exact answer in a standard usable form. For binomial denominators, expand both numerator and denominator carefully. The middle terms of conjugates cancel, which is why (a+b)(ab)=a2b2 (a+b)(a-b)=a^2-b^2 . Write a final line that shows the denominator is rational. This makes it easy for a marker to see that the requested form, not just an equivalent form, has been reached.

One-minute retrieval: Rationalising Denominators

Close the worked solution. From memory, state its central rule, name one condition that makes it valid, and reconstruct one check that would catch a typical exam error.

Rationalise 1/31/\sqrt3.

Rationalise 2/72/\sqrt7.

What is the conjugate of 3+23+\sqrt2?

Evaluate (5+3)(53)(5+\sqrt3)(5-\sqrt3).