Finding the Rule of a Quadratic Pattern

35 min
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Finding the Rule of a Quadratic Pattern

For a quadratic rule Tn=an2+bn+cT_n=an^2+bn+c, the constant second difference is 2a2a. Find aa first, then substitute two known terms to solve for bb and cc. Verify the completed rule with a third term. This turns pattern work into a short system of equations rather than trial and error.

Worked reasoning

Second difference 4 gives 2a=42a=4, so a=2a=2. If T1=5T_1=5 and T2=12T_2=12, then 2+b+c=52+b+c=5 and 8+2b+c=128+2b+c=12, giving b=1,c=2b=1,c=2. Rule: 2n2+n+22n^2+n+2.

Exam method

  1. Use second difference to find a. 2. Substitute two term positions. 3. Solve b and c, then test a spare term.

Verify the general term

After finding a proposed TnT_n, test it with a term that was not used to determine the constants. If it works at positions 1, 2 and 5, confidence is much stronger than if it was only fitted to two values. Keep n as the term number, not the term value. In particular, substituting n=1n=1 must produce the first term; that simple check catches many rules with a correct leading coefficient but an incorrect constant.

One-minute retrieval: Finding the Rule of a Quadratic Pattern

Close the worked solution. From memory, state its central rule, name one condition that makes it valid, and reconstruct one check that would catch a typical exam error.

A quadratic pattern has constant second difference 6. Find a in an2+bn+can^2+bn+c.

Use Tn=n2+2nT_n=n^2+2n to find T5T_5.

If the second difference is 10, which leading term is correct?

Complete: for a quadratic sequence, second difference =;__________.